Dynamic Programming
Optimize recursive solutions by storing subproblem results.
DP Basics
Dynamic Programming solves problems by breaking them into subproblems and storing results to avoid recomputation.
Two Approaches
- Memoization (Top-Down) - Recursive with caching
- Tabulation (Bottom-Up) - Iterative, fills table
When to Use DP
- Overlapping subproblems
- Optimal substructure
Fibonacci with DP
Memoization (Top-Down)
fib_memo.c
#include <stdio.h>
#define MAX 100
int memo[MAX];
int fibMemo(int n) {
if (n <= 1) return n;
if (memo[n] != -1) return memo[n];
memo[n] = fibMemo(n - 1) + fibMemo(n - 2);
return memo[n];
}
int main() {
for (int i = 0; i < MAX; i++) memo[i] = -1;
printf("Fib(40) = %d\n", fibMemo(40));
return 0;
}
Tabulation (Bottom-Up)
fib_tab.c
int fibTab(int n) {
if (n <= 1) return n;
int dp[n + 1];
dp[0] = 0;
dp[1] = 1;
for (int i = 2; i <= n; i++)
dp[i] = dp[i - 1] + dp[i - 2];
return dp[n];
}
0/1 Knapsack Problem
knapsack.c
#include <stdio.h>
int max(int a, int b) { return (a > b) ? a : b; }
int knapsack(int W, int wt[], int val[], int n) {
int dp[n + 1][W + 1];
for (int i = 0; i <= n; i++) {
for (int w = 0; w <= W; w++) {
if (i == 0 || w == 0)
dp[i][w] = 0;
else if (wt[i - 1] <= w)
dp[i][w] = max(val[i - 1] + dp[i - 1][w - wt[i - 1]],
dp[i - 1][w]);
else
dp[i][w] = dp[i - 1][w];
}
}
return dp[n][W];
}
int main() {
int val[] = {60, 100, 120};
int wt[] = {10, 20, 30};
int W = 50;
int n = sizeof(val) / sizeof(val[0]);
printf("Maximum value: %d\n", knapsack(W, wt, val, n));
return 0;
}